(7x^2-3)/4=141

Solution for (7x^2-3)/4=141 equation:

(7x^2-3)/4=141

We move all terms to the left:

(7x^2-3)/4-(141)=0

We multiply all the terms by the denominator


(7x^2-3)-141*4=0

We add all the numbers together, and all the variables

(7x^2-3)-564=0

We get rid of parentheses

7x^2-3-564=0

We add all the numbers together, and all the variables

7x^2-567=0

a = 7; b = 0; c = -567;
Δ = b2-4ac
Δ = 02-4·7·(-567)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-126}{2*7}=\frac{-126}{14}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+126}{2*7}=\frac{126}{14}
=9
$